Question

tính gt biểu thức

a) 5\(\dfrac{5}{47}\) + \(\dfrac{37}{53}\) +2,7- \(\dfrac{5}{47}\) + \(\dfrac{6}{53}\)

b) \(42\dfrac{1}{6}\) : (\(-1\dfrac{3}{5}\)) -52\(\dfrac{1}{6}\) : (-1\(\dfrac{3}{5}\))

giúp mình với

Answer 1

a/ \(5\dfrac{5}{47}+\dfrac{37}{53}+2,7-\dfrac{5}{47}+\dfrac{6}{53}\)

= \(\dfrac{240}{47}-\dfrac{5}{47}+\dfrac{37}{53}+\dfrac{6}{53}+2,7\)

=\(\left(\dfrac{240}{47}-\dfrac{5}{47}\right)+\left(\dfrac{37}{53}+\dfrac{6}{53}\right)+2,7\)

= 5 + \(\dfrac{43}{53}\) + 2,7 = \(\dfrac{4511}{530}\)

b/ \(42\dfrac{1}{6}:\left(-1\dfrac{3}{5}\right)-52\dfrac{1}{6}:\left(-1\dfrac{3}{5}\right)\)

= \(\left(42\dfrac{1}{6}-52\dfrac{1}{6}\right):\left(-1\dfrac{3}{5}\right)\)

= \(-10:\left(-1\dfrac{3}{5}\right)\) =25/4