\(\int-\frac{5}{16\left(1-x\right)}+\frac{7}{4\left(1-x\right)^2}-\frac{5}{16\left(x+3\right)}dx\)
= \(-\int\frac{5}{16\left(1-x\right)}dx+\int\frac{7}{4\left(1-x\right)^2}dc-\int\frac{5}{16\left(x+3\right)}dx\)
= \(\frac{5}{16}ln\left|1-x\right|+\frac{7}{4-4x}-\frac{5}{16}ln\left|x+3\right|\)+C