`A=x-\sqrt{x-1}` `ĐK: x >= 1`
`A=x-1-\sqrt{x-1}+1`
`A=(\sqrt{x-1})^2-2\sqrt{x-1} . 1/2+1/4+3/4`
`A=(\sqrt{x-1}-1/2)^2+3/4`
Với `x >= 1<=>(\sqrt{x-1}-1/2)^2 >= 0`
`<=>(\sqrt{x-1}-1/2)^2+3/4 >= 3/4`
Hay `A >= 3/4`
Dấu "`=`" xảy ra `<=>\sqrt{x-1}=1/2<=>x=5/4`