a: \(f\left(2\right)=\dfrac{2-2}{\left(2+1\right)^2}=0\)
\(f\left(0\right)=\dfrac{0-2}{\left(0+1\right)^2}=-2\)
\(f\left(-2\right)=\dfrac{-2-2}{\left(-2+1\right)^2}=-4\)
b: \(f\left(3\right)=2\left|3-1\right|+3\cdot3-2=4-2+9=11\)
\(f\left(-2\right)=2\left|-2-1\right|+3\left|-2\right|-2=6+6-2=10\)
\(f\left(-1\right)=2\left|-1-1\right|+3\left|-1\right|-2=2\cdot2+3-2=5\)