a) A = \(\dfrac{\left(0,5-\dfrac{1}{3}\right)}{2}+\dfrac{1}{3}-\left(\dfrac{-1}{6}\right):\left(-2\right)\)
A = \(\dfrac{\left(\dfrac{1}{6}\right)}{2}+\dfrac{1}{3}+\dfrac{1}{6}:\left(-2\right)\)
A = \(\dfrac{1}{12}+\dfrac{1}{3}+\left(\dfrac{-1}{12}\right)\)
A = \(\dfrac{1}{3}\)
b) \(x-\dfrac{1}{2}=\dfrac{2}{3}\)
=> \(x=\dfrac{2}{3}+\dfrac{1}{2}\)
=> \(x=\dfrac{7}{6}\)
Vậy : \(x=\dfrac{7}{6}\)
1. Tính giá trị biểu thức :
A = (0,5 - \(\dfrac{1}{3}\)) : 2 + \(\dfrac{1}{3}\) - (-\(\dfrac{1}{6}\)) : (-2)
A = \(\dfrac{1}{2}-\dfrac{1}{3}\) : 2 + \(\dfrac{1}{3}\) - \(\dfrac{1}{12}\)
A = \(\dfrac{1}{6}\) : 2 + \(\dfrac{1}{3}\) - \(\dfrac{1}{12}\)
A = \(\dfrac{1}{12}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{12}\)
A = \(\dfrac{5}{12}-\dfrac{1}{12}\)
A = \(\dfrac{4}{12}\)
A = \(\dfrac{1}{3}\)
2. Tìm x, biết :
x - \(\dfrac{1}{2}=\dfrac{2}{3}\)
x = \(\dfrac{2}{3}+\dfrac{1}{2}\)
x = \(\dfrac{7}{6}\)