Ta có :
\(x+y=2\)
\(\Rightarrow\left(x+y\right)^2=2^2\)
\(x^2+y^2+2xy=4\)
\(\Rightarrow10+2xy=4\)
\(\Rightarrow2xy=-6\)
\(\Rightarrow xy=-3\)
\(\Rightarrow A=x^3+y^3\)
\(=\left(x+y\right)\left(x^2+y^2-xy\right)\)
\(=2.\left[10-\left(-3\right)\right]\)
\(=2.13\)
\(=26\)
Vậy \(A=26\)