\(A=2\sqrt{2}+3\sqrt{2}-4\sqrt{2}=\sqrt{2}\)
B=6+18-8=16
\(A=2\sqrt{2}+3\sqrt{2}-4\sqrt{2}=\sqrt{2}\\ B=2\cdot3+3\cdot6-8=6+18-8=16\)
a =2 \(\sqrt{2}\) + 3\(\sqrt{2}\)- 4\(\sqrt{2}\)
=\(\sqrt{2}\)
b= 2.3 + 3.4\(\sqrt{2}\)-\(6\sqrt{2}\)
= 3+( 12-6)\(\sqrt{2}\)
= 3+ 6\(\sqrt{2}\)