Question

Tính

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)

Answer 1

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\\ =>\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}-\dfrac{5}{9}=\dfrac{8}{27}\\ =>2+\dfrac{3}{4}x=\dfrac{7}{9}:\dfrac{8}{27}=\dfrac{21}{8}\\ =>\dfrac{3}{4}x=\dfrac{21}{8}-2=\dfrac{5}{8}\\ =>x=\dfrac{5}{8}:\dfrac{3}{4}=\dfrac{5}{6}\)

Answer 2

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7/9 : ( 2 + 3/4 x) = 23/27 - 5/9

7/9 : ( 2 + 3/4 ) = 8/ 27

2 + 3/4 x = 7/9 : 8/ 27

2 + 3/4 x = 21/8

3/4 x = 21/8 - 2

3/4 x = 5/8

x = 5/8 : 3/4

x = 5/6

Vậy :\(x=\dfrac{5}{6}\)

Answer 3

7/9:(2+3/4x)+5/9=23/27

7/9:(2+3/4x) = 23/27 - 5/9 = 2/3

2+3/4x = 7/9:2/3=7/6

3/4x = 7/6-2= -5/6

x = -5/6 : 3/4 = - 20/18

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Answer 4

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)

=> \(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}-\dfrac{5}{9}\)

=> \(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}-\dfrac{15}{27}\)

=> \(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{8}{27}\)

=> \(2+\dfrac{3}{4}x=\dfrac{7}{9}:\dfrac{8}{27}\)

=> \(2+\dfrac{3}{4}x=\dfrac{7}{9}.\dfrac{27}{8}\)

=> \(2+\dfrac{3}{4}x=\dfrac{7.3}{1.8}\)

=> \(2+\dfrac{3}{4}x=\dfrac{21}{8}\)

=> \(\dfrac{3}{4}x=\dfrac{21}{8}-2\)

=> \(\dfrac{3}{4}x=\dfrac{21}{8}-\dfrac{16}{8}\)

=> \(\dfrac{3}{4}x=\dfrac{5}{8}\)

=> \(x=\dfrac{5}{8}:\dfrac{3}{4}\)

=> \(x=\dfrac{5}{8}.\dfrac{4}{3}\)

=> \(x=\dfrac{5}{6}\)

Vậy x = \(\dfrac{5}{6}\)

Answer 5

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)-\dfrac{5}{9}=\dfrac{23}{27}\)

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}+\dfrac{5}{9}=\dfrac{38}{27}\)

\(2+\dfrac{3}{4}x=\dfrac{7}{9}:\dfrac{38}{27}=\dfrac{21}{38}\)

\(\dfrac{3}{4}x=\dfrac{21}{38}-2=-\dfrac{55}{38}\)

\(x=-\dfrac{55}{38}:\dfrac{3}{4}=-\dfrac{110}{57}\)

Answer 6

Đáng ra đề bài phải là:

Tìm x

Answer 7

\(\dfrac{7}{9}\): ( 2 + \(\dfrac{3}{4}\)x ) + \(\dfrac{5}{9}\)= \(\dfrac{23}{27}\)

\(\dfrac{7}{9}\): ( 2 + \(\dfrac{3}{4}\)x ) = \(\dfrac{23}{27}\) - \(\dfrac{5}{9}\)

\(\dfrac{7}{9}\): ( 2 + \(\dfrac{3}{4}\)x ) = \(\dfrac{8}{27}\)

2 + \(\dfrac{3}{4}\)x = \(\dfrac{7}{9}\) : \(\dfrac{8}{27}\)

2 + \(\dfrac{3}{4}\)x = \(\dfrac{8}{21}\)

\(\dfrac{3}{4}\)x = \(\dfrac{8}{21}\)- 2

\(\dfrac{3}{4}\)x = \(\dfrac{-34}{21}\)

x = \(\dfrac{-34}{21}\): \(\dfrac{3}{4}\)

x = \(\dfrac{-136}{63}\)

Answer 8

\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)

\(\Rightarrow\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}-\dfrac{5}{9}=\dfrac{8}{27}\)

\(\Rightarrow2+\dfrac{3}{4}x=\dfrac{7}{9}:\dfrac{8}{27}=\dfrac{21}{8}\)

\(\Rightarrow\dfrac{3}{4}x=\dfrac{21}{8}-2=\dfrac{5}{8}\)

\(\Rightarrow x=\dfrac{5}{8}:\dfrac{3}{4}=\dfrac{5}{6}\)

Vậy, \(x=\dfrac{5}{6}\)