Question

tính \(\dfrac{-6^3-3.\left(-6\right)^2-\left(-3\right)^3}{-13}\)

Answer 1

\(\dfrac{-6^3-3.\left(-6\right)^2-\left(-3\right)^3}{-13}\)=\(\dfrac{\left(-3.2\right)^3-3.\left(-3.2\right)^2-\left(-3\right)^3}{-13}\)

=\(\dfrac{-3^3.2^3-3.\left(-3\right)^2.2^2-\left(-3\right)^3}{-13}\)=\(\dfrac{-3^3.2^3+\left(-3\right)^3.2^2-\left(-3\right)^3}{-13}\)

=\(\dfrac{-3^3.\left(2^3+2^2-1\right)}{-13}\)=\(\dfrac{-297}{-13}\)=\(\dfrac{297}{13}\)

Answer 2

\(\dfrac{-6^3-3.\left(-6\right)^2-\left(-3\right)^3}{-13}\)

\(=\dfrac{-216-\left(-108\right)-\left(-27\right)}{-13}\)

\(=\dfrac{-81}{-13}\)

\(=\dfrac{81}{13}\)

Answer 3

\(\dfrac{-6^3-3.\left(-6\right)^2-\left(-3\right)^3}{-13}\)=\(\dfrac{-216-3.36+27}{-13}\)=\(\dfrac{-216-108+27}{-13}\)

=\(\dfrac{-297}{-13}\)=\(\dfrac{297}{13}\)