\(\widehat{COB} = 4 \widehat{DOB}\)
\(\widehat{COB} + \widehat{DOB} = 180^O\) (kề bù)
\(\Rightarrow\)\(\widehat{COB} = 180^O : 5 = 36^O\)
\(\Rightarrow\)\(\widehat{DOB} = 180^O - 36^O = 144^O\)
Ta có:
\(\widehat{COB} = \widehat{AOD}\) (đối đỉnh)
mà \(\widehat{COB} = 36^O\) (cmt)
\(\Rightarrow\)\(\widehat{AOD} = 36^O\)
Vậy ..................