\(D=\dfrac{2\sqrt{3-\sqrt{4+2\sqrt{3}}}}{\sqrt{6}-\sqrt{2}}\)
\(=\dfrac{2\sqrt{3-\sqrt{3}-1}}{\sqrt{6}-\sqrt{2}}=\dfrac{2\sqrt{2-\sqrt{3}}}{\sqrt{6}-\sqrt{2}}\)
\(=\dfrac{2\sqrt{4-2\sqrt{3}}}{2\left(\sqrt{3}-1\right)}=\dfrac{2\left(\sqrt{3}-1\right)}{2\left(\sqrt{3}-1\right)}=1\)