a) \(A=\dfrac{2}{\sqrt{3}+1}+\dfrac{6}{\sqrt{3}-1}+1\)
\(=\dfrac{3\left(\sqrt{3}-1\right)}{2}+\dfrac{6\left(\sqrt{3}+1\right)}{2}+\dfrac{2}{2}\)
\(=\dfrac{3\left(\sqrt{3}-1\right)+6\left(\sqrt{3}+1\right)+2}{2}\)
\(=\dfrac{3\sqrt{3}-3+6\sqrt{3}+6+2}{2}\)
\(=\dfrac{9\sqrt{3}+5}{2}\)