Question

Tính

B=\(\dfrac{\left(\dfrac{2}{3}\right)^3.\left(\dfrac{-3}{4}\right)^2.\left(-1\right)^{2011}}{\left(\dfrac{2}{5}\right)^2.\left(\dfrac{-5}{12}\right)^3}\)

Answer 1

\(B=\dfrac{\left(\dfrac{2}{3}\right)^3\cdot\left(-\dfrac{3}{4}\right)^2\cdot\left(-1\right)^{2011}}{\left(\dfrac{2}{5}\right)^2\cdot\left(-\dfrac{5}{12}\right)^3}\)

\(B=\dfrac{\dfrac{2}{3}\cdot\left(-\dfrac{3}{4}\cdot\dfrac{2}{3}\right)^2\cdot\left(-1\right)}{-\dfrac{5}{12}\left(-\dfrac{5}{12}\cdot\dfrac{2}{5}\right)^2}\)

\(B=\dfrac{-\dfrac{2}{3}\cdot\dfrac{1}{4}}{-\dfrac{5}{12}\cdot\dfrac{1}{36}}=-\dfrac{1}{6}:-\dfrac{5}{432}\)

\(B=\dfrac{72}{5}\)