a: \(=\dfrac{2}{5}x^2y^2-2x^2y+4xy^2\)
b: \(=x^2y^2+5xy-xy-5=x^2y^2+4xy-5\)
c: \(=-10x^5+5x^3-2x^2\)
d: \(=x^3-2x^2y+3x^2y-6xy^2=x^3+x^2y-6xy^2\)
a: \(=\dfrac{2}{5}x^2y^2-2x^2y+4xy^2\)
b: \(=x^2y^2+5xy-xy-5=x^2y^2+4xy-5\)
c: \(=-10x^5+5x^3-2x^2\)
d: \(=x^3-2x^2y+3x^2y-6xy^2=x^3+x^2y-6xy^2\)
thực hiện phép tính
a.\(-2xy^2.\left(x^3y-2x^2y^2+5xy^3\right)\)
b.\(\left(-2x\right).\left(x^3-3x^2-x+1\right)\)
c.3x\(^2\left(2x^3-x+5\right)\)
d.\(\left(-10x^3+\frac{2}{5}y-\frac{1}{3}z\right).\left(-\frac{1}{2}xy\right)\)
e.\(\left(3x^2y-6xy+9x\right).\left(-\frac{4}{3}xy\right)\)
f.\(\left(4xy+3y-5x\right).x^2y\)
Bài 1: Thu gọn
a) \(\frac{1}{5}x^4y^3-3x^4y^3\)
b) \(5x^2y^5-\frac{1}{4}x^2y^5\)
c) \(\frac{1}{7}x^2y^3.\left(-\frac{14}{3}xy^2\right)-\frac{1}{2}xy.\left(x^2y^{\text{4}}\right)\)
d) \(\left(3xy\right)^2.\left(-\frac{1}{2}x^3y^2\right)\)
e) \(-\frac{1}{4}xy^2+\frac{2}{5}x^2y+\frac{1}{2}xy^2-x^2y\)
f) \(\frac{1}{2}x^4y.\left(-\frac{2}{3}x^3y^2\right)-\frac{1}{3}x^7y^3\)
g) \(\frac{1}{2}x^2y.\left(-10x^3yz^2\right).\frac{1}{4}x^5y^3z\)
h) \(4.\left(-\frac{1}{2}x\right)^2-\frac{3}{2}x.\left(-x\right)+\frac{1}{3}x^2\)
i) \(1\frac{2}{3}x^3y.\left(\frac{-1}{2}xy^2\right)^2-\frac{5}{4}.\frac{8}{15}x^3y.\left(-\frac{1}{2}xy^2\right)^2\)
k) \(-\frac{3}{2}xy^2.\left(\frac{3}{4}x^2y\right)^2-\frac{3}{5}xy.\left(-\frac{1}{3}x^4y^3\right)+\left(-x^2y\right)^2.\left(xy\right)^2\)
n) \(-2\frac{1}{5}xy.\left(-5x\right)^2+\frac{3}{4}y.\frac{2}{3}\left(-x^3\right)-\frac{1}{9}.\left(-x\right)^3.\frac{1}{3}y\)
m) \(\left(-\frac{1}{3}xy^2\right)^2.\left(3x^2y\right)^3.\left(-\frac{5}{2}xy^2z^3\right)^{^2}\)
p) \(-2y.\left|2\right|x^4y^5.\left|-\frac{3}{4}\right|x^3y^2z\)
Bài 1: Thu gọn đơn thức ( a là hằng só )
a) \(1\dfrac{1}{4}x^2y\left(\dfrac{-5}{6}xy\right)^0.\left(-2\dfrac{1}{3}xy\right)\)
b) \(\dfrac{1}{2}x.\dfrac{1}{4}x^2.\dfrac{x^3}{8}.2y.4y^2.x^3\)
c) \(\left(\dfrac{-9}{2}\right)^3.3xy\left(4a^2x^3\right)\left(4\dfrac{1}{3}ay^2\right)\)
d) \(\left(\dfrac{1}{3}xy^2\right)^3\left(\dfrac{-3}{7}x^4y\right)^2\)
Bài 1: Thu gọn các đơn thức, xác định hệ số, phần biế, tìm bậc của các đơn thức sau:
a, \(A=\frac{2}{3}x^2y.\left(-\frac{3}{4}y\right).\left(-x^2\right)\)
b, \(C=0,12y^2.\left(-1\frac{1}{3}xy\right)^2.\left(-xy\right)^3\)
c, \(E=1,2.\left(-xy^2\right)^3.\left(-\frac{3}{5}y^2\right).\left(-0,5x^2y^3\right)^2\)
d, \(B=\frac{11}{12}\left(y^2\right)^3.\left(-\frac{1}{33}x^3\right).\left(-x\right)^2\)
e, \(D=2x^3y.\left(-\frac{1}{2}xy\right)^3.x^2y\)
f, \(F=-2\frac{1}{3}x^3z^2.\left(\frac{1}{3}xy^2z\right)^2.\left(6xyz\right)\)
Tìm đa thức M , biết :
a) \(M-\left(\frac{1}{2}x^2y-5xy^2+x^3-y^3\right)=\frac{3}{4}xy^2-2x^2y+\)\(2y^3-\frac{1}{3}x^3\)
b)\(\left(-\frac{1}{3}x^3y^3+5x^2y^2-\frac{5}{2}xy\right)-M=xy-\frac{1}{6}x^3y^3-3x^2y^2\)
c)\(\left(\frac{2}{7}xy^4-5x^5+7x^2y^3-3\right)+M=0\)
tìm x,y biết
\(\left|2x-5\right|+\left|3y+1\right|=0\)
\(\left|3x-4\right|+\left|3y-5\right|=0\)
\(|16-|x||+\left|5y-2\right|=0\)
\(\left|2x-5\right|+\left|xy-3y+2\right|=0\)
a,\(\left|3x-4\right|+\left|3y+5\right|=0\) b,\(\left|x+\dfrac{19}{5}\right|+\left|y+\dfrac{1890}{1975}\right|+\left|z-2004\right|=0\) c,\(\left|x+\dfrac{9}{2}\right|+\left|y+\dfrac{4}{3}\right|+\left|z+\dfrac{7}{2}\right|\le0\)
d,\(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{1}{5}\right|+\left|x+y+z\right|=0\) e,\(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{2}{5}\right|+\left|z+\dfrac{1}{2}\right|\le0\)
Giups mình giải bài tìm x,y,z này nhé!!! Cảm ơn nhiều ạ!!!
1.Thu gọn các biểu thức sau :
a)\(x^2\)(\(\dfrac{-1}{3}y\)).\(\dfrac{1}{5}\)\(x^4\)
b)-y2\(x^3y\dfrac{4x}{5}ab^5\)
c)(\(-4^2\)).(\(\dfrac{3}{4}\))\(v^3\left(\dfrac{-2}{5}\right)uv\)
d)8.\(\left(-4\right)^3\).5\(\left(uv\right)^2.\left(-3v\right)^3\)
e)-10y\(\left(2yz\right)^3.\left(-5z\right)^2\)
f)2ax.\(\left(-y\right)^2-x\left(\dfrac{-2}{3}y\right)^2+bx\left(by\right)^2\)
Tìm x :
a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
c) \(\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2009}{5}+\dfrac{x+2020}{6}\)
d)\(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+18\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
Help me , bn nào giải đc bài nò thì giải nha !!! =))