Ta có: \(-\left(38-x\right)-\left(37-x\right)=30-x\)
\(\Leftrightarrow-38+x-37+x-30+x=0\)
\(\Leftrightarrow3x-105=0\)
\(\Leftrightarrow3x=105\)
hay x=35
Vậy: x=35
-(38-x)-(37-x)=30-x
⇔-38+x-37+x=30-x
⇔x+x+x=30+38+37
⇔3x=105
⇔x=105 : 3
⇔x=35
Vậy x=35.