Ta có: \(\dfrac{x}{2}=\dfrac{y}{3};\dfrac{y}{6}=\dfrac{z}{5}\)
\(\Rightarrow\dfrac{x}{4}=\dfrac{y}{6}=\dfrac{z}{5}\)
\(\Rightarrow\dfrac{2x}{8}=\dfrac{3y}{18}=\dfrac{z}{5}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{2x}{8}=\dfrac{3y}{18}=\dfrac{z}{5}=\dfrac{2x+3y-z}{8+18-5}=\dfrac{84}{21}=4\)
\(\Rightarrow\left[{}\begin{matrix}x=16\\y=24\\z=20\end{matrix}\right.\)