a: \(\left(x+1\right)+\left(x+3\right)+...+\left(x+99\right)=0\)
\(\Leftrightarrow50x+2500=0\)
=>50x=-2500
hay x=-50
c: (x-7)(x+3)<0
=>x+3>0 và x-7<0
=>-3<x<7
b: (x-3)(2y+1)=7
\(\Leftrightarrow\left(x-3;2y+1\right)\in\left\{\left(1;7\right);\left(7;1\right);\left(-1;-7\right);\left(-7;-1\right)\right\}\)
hay \(\left(x,y\right)\in\left\{\left(4;3\right);\left(10;0\right);\left(2;-4\right);\left(-4;-1\right)\right\}\)