\(x:4\dfrac{1}{3}=-2,5\)
\(\Leftrightarrow x:\dfrac{13}{3}=-2,5\)
\(\Leftrightarrow x=-2,5.\dfrac{13}{3}\)
\(\Leftrightarrow x=-\dfrac{65}{6}\)
\(x:4\dfrac{1}{3}=-2,5\Rightarrow x:\dfrac{13}{3}=-2,5\Rightarrow x=-2,5.\dfrac{13}{3}\Rightarrow x=-\dfrac{65}{6}\)
Ta có: \(x:4\dfrac{1}{3}=-2.5\)
\(\Leftrightarrow x:\dfrac{13}{3}=-\dfrac{5}{2}\)
\(\Leftrightarrow x=\dfrac{-5}{2}\cdot\dfrac{13}{3}=\dfrac{-65}{6}\)
Vậy: \(S=\left\{-\dfrac{65}{6}\right\}\)