Question

Tìm x

\(x^{10}\) = \(x^2\)

Answer 1

\(x^{10}=x^2\)

\(\Rightarrow x^{10}-x^2=0\)

\(\Rightarrow x^2.\left(x^8-1\right)=0\)

\(\Rightarrow x^2=0\) hoặc \(x^8-1=0\)

+) \(x^2=0\Rightarrow x=0\)

+) \(x^8-1=0\)

\(\Rightarrow x^8=1\)

\(\Rightarrow x=1\) hoặc \(x=-1\)

Vậy \(x\in\left\{0;1;-1\right\}\)

Answer 2

trình bày nhé

Answer 3

x¹⁰ = x²

=> x¹⁰ - x² = 0

=> x².(x⁸ - 1) = 0

\(\Rightarrow\left[\begin{array}{nghiempt}x^2=0\\x^8-1=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x^8=1\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=1\\x=-1\end{array}\right.\)

Vậy \(x\in\left\{0;1;-1\right\}\)

Answer 4

x^10=x^2

=> x^10-x^2=0

=>x^8.x^2-x^2.1=0

=>x^2.(x^8-1)=0

Vậy ta có 2 trường hợp là 

TH1:x^2=0

=>x^2=0^2

=>x=0

TH2:x^8-1=0

=>x^8=0+1

=>x^8=1

=>x^8=1^8

=>x=1

Vậy x ={1;0}