\(\left(x+1\right)\left(x-2\right)< 0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+1< 0\\x-2< 0\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x< 0-1\\x< 0+2\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x< \left(-1\right)\\x< 2\end{array}\right.\)
Vậy: \(\left(-1\right)< x< 2\)
Tìm x \(\in\) Q , biết :
a ) ( x + 1 )( x - 2 ) < 0
b ) ( x - 2 ) ( x + \(\frac{2}{3}\) ) > 0
Bài 19 : Tìm x \(\in\) Q, biết :
a) (x + 1) (x - 2) < 0 ; b) (x - 2) \(\left(x+\frac{2}{3}\right)>0\)
Tìm x , y \(\in\) Z biết : xy + x + y - 2 = 0
Tìm \(x\in Q\) biết :
\(\left(x-2\right)\left(x+\frac{2}{3}\right)>0\)
tìm x \(\in\) Q biết
\(a,\left|2,5-x\right|=1,3\)
\(b,1,6-\left|x-0,2\right|=0\)
\(c,\left|x-1,5\right|+\left|2,5-x\right|=0\)
\(d,\left(x-\frac{1}{2}\right)^2=0\)
\(e,\left(x-2\right)^2=1\)
\(f\left(2x-1\right)^3=-8\)
tìm x thuộc q biết: (x+1).(x-2)<0
Tìm x thuộc Q, biết:
a) (x+1)(x-2)<0
b)(x-2)\(\left(x+\frac{2}{3}\right)\)>0
Tìm \(x\in Q\), biết:
\(2^{x+3}+2^{x+1}=320\)
Tìm \(x\in Q\), biết:
\(\left|x-3\right|+\left|3x+4\right|-\left|2x+1\right|=0\)
