Question

Tìm x

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

Answer 1

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)

\(\Rightarrow x^2+2x-3=x^2-4\)

\(\Rightarrow2x=-1\)

\(\Rightarrow x=-\frac{1}{2}\)

Answer 2

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

\(\Leftrightarrow\left(x-1\right).\left(x+3\right)=\left(x+2\right).\left(x-2\right)\)

\(\Leftrightarrow x^2+3x-x-3=x^2-4\)

\(\Leftrightarrow2x=-1\)

\(\Leftrightarrow x=-\frac{1}{2}\)

Chúc bạn học tốt