\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
\(\Rightarrow\left(3x+2\right)\left(5x+1\right)=\left(3x-1\right)\left(5x+7\right)\)
\(\Rightarrow15x^2+10x+3x+2=15x^2-5x+21x-7\)
\(3x=9\)
\(x=3\)
Ta có: (3x+2)(5x+1)=(5x+7)(3x-1) (ĐKXĐ: x khác -7/5, x khác -1/5)
=> 15x2+13x+2=15x2+16x-7
=> 3x-9=0 =>x=3 (chọn)