\(5-2\left|x+7\right|=4x-1\) (1)
+)TH1: \(x+7\ge0\Leftrightarrow x\ge-7\) thì
(1) \(\Leftrightarrow5-2\left(x+7\right)=4x-1\)
\(\Leftrightarrow5-2x-14=4x-1\)
\(\Leftrightarrow-6x=8\)
\(\Leftrightarrow x=-\frac{4}{3}\left(tm\right)\)
+)TH2: \(x+7< 0\Leftrightarrow x< -7\) thì
(1) \(\Leftrightarrow5+2\left(x+7\right)=4x-1\)
\(\Leftrightarrow5+2x+14=4x-1\)
\(\Leftrightarrow-2x=-20\)
\(\Leftrightarrow x=10\left(ktm\right)\)
Vậy x=-4/3
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