Question

Tìm x; y thuộc Z biết

|x-2|+2(y-1)⁴=0

Answer 1

Ta thấy :\(\left|x-2\right|\ge0\)

\(2\left(y-1\right)^4\ge0\)

Từ đó suy ra : \(\left|x-2\right|+2\left(y-1\right)^4\ge0\)

Mà để : \(\left|x-2\right|+2\left(y-1\right)^4=0\Leftrightarrow\left\{\begin{matrix}\left|x-2\right|=0\Rightarrow x=2\\2\left(y-1\right)^4=0\Rightarrow y=1\end{matrix}\right.\)

Vậy x = 2 ; y = 1

Answer 2

\(\left|x-2\right|+2\left(y-1\right)^4=0.\\ Khix-2=0v\text{à}2\left(y-1\right)^4=0\\ N\text{ếu}x-2=0;=>x=2\\ N\text{ếu}2\left(y-1\right)^4=0;=>y=1\)

Vậy x=2;y=1