Question

tìm x

x.3/1/4+(-7/6).x-1/2/3=5/12

Answer 1

x.\(3\dfrac{1}{4}\)+\(\dfrac{-7}{6}\).x-\(1\dfrac{2}{3}\)=\(\dfrac{5}{12}\)

x.\(\dfrac{13}{4}\)+\(\dfrac{-7}{6}\)x-\(\dfrac{5}{3}\)=\(\dfrac{5}{12}\)

\(\dfrac{13}{4}\)x+\(\dfrac{-7}{6}\)x=\(\dfrac{5}{12}\)+\(\dfrac{5}{3}\)

\(\dfrac{13}{4}\)x+\(\dfrac{-7}{6}\)x=\(\dfrac{25}{12}\)

\(\dfrac{25}{12}\)x=\(\dfrac{25}{12}\)

x=1

Vậy x=1

Answer 2

\(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)

\(x.\dfrac{13}{4}+\left(\dfrac{-7}{6}\right).x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(x.\dfrac{13}{4}+x.\left(\dfrac{-7}{6}\right)=\dfrac{5}{12}+\dfrac{5}{3}\)

\(x.\dfrac{13}{4}+x.\left(\dfrac{-7}{6}\right)=\dfrac{25}{12}\)

\((\dfrac{13}{4}+\dfrac{-7}{6}).x=\dfrac{25}{12}\)

\(\dfrac{25}{12}.x=\dfrac{25}{12}\)

\(x=\dfrac{25}{12}:\dfrac{25}{12}\)

\(x=1\)