\(x^2+4=3x+2\sqrt{x-1}\)
\(\Leftrightarrow x^2+4-3x-2\sqrt{x-1}=0\)
\(\Leftrightarrow\left(x^2-4x+4\right)+\left(x-1-2\sqrt{x-1}+1\right)=0\)
\(\Leftrightarrow\left(x-2\right)^2+\left(\sqrt{x-1}-1\right)^2=0\)
\(\Leftrightarrow x=2\)
Tìm x:
1, \(\sqrt{1-2x}+\sqrt{1+2x}=\sqrt{4+x}\)
2,\(\sqrt{3x+1}-\sqrt{2-x}=\sqrt{3x-2}\)
3, \(\sqrt{x-2\sqrt{x-1}}+\sqrt{x+2\sqrt{x-1}}=4\)
4, \(3x^2-6x-4=4\left(x-1\right)\sqrt{3x+1}\)
tìm x
a,\(\sqrt{3+\sqrt{x}}=4\)
b,\(\sqrt{x+3}=\sqrt{1-5x}\)
c,\(\sqrt{x^2+6x+9}=3x-1\)
Tìm x:
a)\(\dfrac{1}{3}\sqrt{x-1}+2\sqrt{4x-4}-12\sqrt{\dfrac{x-1}{25}}=\dfrac{29}{15}\)
b)\(\dfrac{3x-2}{\sqrt{x-1}}-\sqrt{x+1}=\sqrt{2x-3}\)
Tìm x:
a. \(\sqrt{9x^2}=2x+1\)
b. \(\sqrt{x^2+6x+9}=3x-1\)
c. \(\sqrt{x^2-2x+4}=2x-3\)
Giải phương trình vô tỉ:
1/ \(\sqrt{x^2+12}+5=3x+\sqrt{x^2+15}\)
2/ \(\sqrt{3x^2-5x+1}-\sqrt{x^2-2}=\sqrt{3\left(x^2-x+1\right)}-\sqrt{x^2-3x+4}\)
3/ \(\sqrt[5]{x-1}+\sqrt[3]{x+8}=-x^3+1\)
4/ \(\sqrt{5-x^6}+\sqrt[3]{3x^4-2}=1\)
Tìm x biết:
a.\(\sqrt{18x}+2\sqrt{8x}-3\sqrt{2x}=12\)
b.\(\sqrt{9x+18}+2\sqrt{36x+72}-\sqrt{4x+8}=26\)
c.\(\sqrt{\left(x-2\right)^2}=10\)
d.\(\sqrt{9x^2-6x+1}=15\)
e.\(\sqrt{3x+4}=3x-8\)
Tìm ĐK để căn thức sau xác định:
a) \(\sqrt{x^2+3x-10}\)
b) \(\sqrt{\dfrac{4x-4-x^2}{5}}\)
c) \(\sqrt{x-4\sqrt{x-4}}\)
\(\sqrt{3x^2-5x+1}-\sqrt{x^2-2}=\sqrt{3\left(x^2-x-1\right)}-\sqrt{x^2-3x+4}\)
Tìm điều kiện xác định
\(A=\sqrt{x^2-5x+6}\)
\(B=\dfrac{x}{\sqrt{7x^2-8}}\)
\(C=\sqrt{-9x^2+6x-1}-\dfrac{1}{\sqrt{x^2+x+2}}\)
\(D=\sqrt{3-x^2}-\sqrt{\dfrac{2021}{3x+2}}\)
\(E=\sqrt{\dfrac{3x^2}{2x+1}-1}\)
\(F=\sqrt{25x^2-10x+1}+\dfrac{1}{1-5x}\)
Rút gon A=\(\sqrt[3]{\dfrac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}}{2}}+\sqrt[3]{\dfrac{x^3-3x-\left(x^2-1\right)\sqrt{x^2-4}}{2}}\)
