1. \(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{4}{7}\Rightarrow\left\{{}\begin{matrix}\dfrac{4}{x}=\dfrac{4}{7}\\\dfrac{y}{21}=\dfrac{4}{7}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=7\\y=12\end{matrix}\right.\)
1: Ta có: \(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}\)
\(\Leftrightarrow\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{4}{7}\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{4}{x}=\dfrac{4}{7}\\\dfrac{y}{21}=\dfrac{4}{7}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=7\\y=12\end{matrix}\right.\)
Vậy: (x,y)=(7;12)
2) Ta có: \(\dfrac{x}{y}=\dfrac{2}{7}\)
nên \(\dfrac{x}{2}=\dfrac{y}{7}\)