Question

Tìm x

\(\sqrt{x^2+x}=x\)

Answer 1

ĐK: \(x\ge0\)

Ta có \(\sqrt{x^2+x}=x\Leftrightarrow\left(\sqrt{x^2+x}\right)=x^2\Leftrightarrow x^2+x=x^2\Leftrightarrow x=0\left(tm\right)\)

Vậy S={0}

Answer 2

\(\sqrt{x^2+x}=x\Leftrightarrow x^2+x=x^2\)

\(\Leftrightarrow x=0\)

Answer 3

\(\sqrt{x^2+x}=x\\ x^2+x=x^2\\ x=0\)