\(DK:x\ge-3\)
\(\sqrt{2x-1}+\sqrt{x}+\sqrt{x+3}=4\Leftrightarrow\sqrt{x}+\sqrt{x+3}=4-\sqrt{2x-1}\Rightarrow\left(\sqrt{x}+\sqrt{x+3}\right)^2=\left(4-\sqrt{2x-1}\right)^2\Leftrightarrow2x+3+2\sqrt{x^2+3x}=2x+3-8\sqrt{2x-1}\Leftrightarrow2\sqrt{x^2+3x}=-8\sqrt{2x-1}\Rightarrow\left\{{}\begin{matrix}x^2+3x=0\\2x-1=0\end{matrix}\right.hptvn\)