Question

Tìm x

\(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)

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Answer 1

Ta có: \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\frac{1}{2}=\frac{1}{4}\\x+\frac{1}{2}=-\frac{1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{4}-\frac{1}{2}=\frac{1}{4}-\frac{2}{4}=\frac{-1}{4}\\x=\frac{-1}{4}-\frac{1}{2}=\frac{-1-2}{4}=-\frac{3}{4}\end{matrix}\right.\)

Vậy: \(x\in\left\{\frac{-1}{4};\frac{-3}{4}\right\}\)