Question

Tìm x: \(\left[\dfrac{1}{2}x^2\left(2x-1\right)^m-\dfrac{1}{2}x^{m+2}\right]:\dfrac{1}{2}x^2=0\)

Answer 1

\(\left[\dfrac{1}{2}x^2\left(2x-1\right)^m-\dfrac{1}{2}x^{m+2}\right]:\dfrac{1}{2}x^2=0\)

<=>\(\left[\dfrac{1}{2}x^2\left(2x-1\right)^m-\dfrac{1}{2}x^{m+2}\right].2x^2=0\)

<=> \(\left[\dfrac{1}{2}x^2\left(2x-1\right)^m-\dfrac{1}{2}x^{m+2}\right]=0\) hoặc \(2x^2=0\)

<=> \(\dfrac{1}{2}x^2\left[\left(2x-1\right)^m-\dfrac{1}{2}x^m\right]=0\) hoặc x=0

<=> \(\left(2x-1\right)^m-\dfrac{1}{2}x^m=0\) hoặc x=0

\(nhưng\left(2x-1\right)^m-\dfrac{1}{2}x^mkhác0\)

=> ta chỉ tìm được x=0