\(\left(3x+1\right)^3=27\Leftrightarrow3x+1=3\Leftrightarrow3x=2\Leftrightarrow x=\dfrac{2}{3}\)
Vậy ...
\(\left(3x+1\right)^3=27\)
\(\Leftrightarrow\left(3x+1\right)^3=3^3\)
\(\Leftrightarrow3x+1=3\Rightarrow3x=2\Rightarrow x=\dfrac{2}{3}\)
Vậy x = \(\dfrac{2}{3}\)