\(\left(x-2\right)\left(x+\frac{2}{3}\right)>0\)
\(\Leftrightarrow\begin{cases}x-2>0\\x+\frac{2}{3}>0\end{cases}\) hoặc \(\begin{cases}x-2< 0\\x+\frac{2}{3}< 0\end{cases}\)
\(\Leftrightarrow\begin{cases}x>2\\x>-\frac{2}{3}\end{cases}\) hoặc \(\begin{cases}x< 2\\x< -\frac{2}{3}\end{cases}\)
\(\Leftrightarrow x>2\) hoặc \(x< -\frac{2}{3}\)
Tìm x,y,z biết:
\(\left|x-\frac{1}{2}\right|+\left|y+\frac{3}{2}\right|+\left|x+y-z-\frac{1}{2}\right|=0\)
1.Tìm x \(^{_{ }\in}\) Z biết :
\(\left(x^2-1\right)\left(x^2-4\right)< 0\)
2.*Tìm số nguyên x sao cho :
a. \(\left(x^2-4\right).\left(x^2-10\right)\)
b. \(x\left(x-3\right)< 0\)
3. Tìm các số nguyên x;y sao cho :
\(\left(x-3\right)\left(y+2\right)=-5\)
Giúp tớ bài này nhé! Help me
Tìm \(x\in Z\) biết :
\(a.\left(x-4\right).\left(x-7\right)=0\)
\(b:x.\left(x+3\right)=0\)
\(c:\left(x-2\right)\left(5-x\right)=0\)
\(d:\left(x-1\right).\left(x^2+1\right)=0\)
tìm x biết :
a) \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
b) \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
c) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
tim x
\(a,\left|\frac{4}{7}-x\right|+\frac{2}{5}=0\)
\(b,6-\left|\frac{1}{4}x+\frac{2}{5}\right|=0\)
\(c,\left|x-\frac{1}{3}\right|+\left|2-\frac{4}{5}\right|=0\)
Làm phép tính sau khi bỏ dấu GTTĐ :
a) \(\left|x+\frac{2}{3}\right|+\left|x-3\right|\) biết rằng x\(\ge\)3
b) \(-\left|x+\frac{2}{5}\right|+\left|\frac{4}{3}-x\right|\)biết rằng x > 2
Bài 1: Tìm \(x\in Z\), biết :
a. \(\left|x\right|+\left|y\right|=0\)
b. \(\left|x\right|+\left|y\right|=2\)
Bài 2: Tìm \(x\in Z\) biết :
\(6< \left|x\right|\le9\)
Tìm x :
\(\frac{3}{\left(x+2\right).\left(x+5\right)}+\frac{5}{\left(x+5\right).\left(x+10\right)}+\frac{7}{\left(x+10\right).\left(x+17\right)}=\frac{x}{\left(xx+2\right).\left(x+17\right)}\)
Giúp mk với 
