\(\frac{x-5}{1}+\frac{x-5}{2}+\frac{x-5}{3}+\frac{x-5}{4}=0\)
\(\Rightarrow\left(x-5\right)\left(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=0\)
Mà \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\ne0\)
\(\Rightarrow x-5=0\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
\(\frac{x-5}{1}+\frac{x-5}{2}+\frac{x-5}{3}+\frac{x-5}{4}=0\)
\(\Rightarrow\left(x-5\right)\left(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=0\)
\(\Rightarrow x-5=0\). Do \(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\ne0\)
\(\Rightarrow x=5\)
\(\frac{X-5}{1}+\frac{X-5}{2}+\frac{X-5}{3}+\frac{X-5}{4}=0\)
=>x-5(\(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\))=0
Mà \(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}>0\)
=>x-5=0
=>x=5
