Ta có:
\(x\left(2+x\right)\left(7-x\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\2+x=0\\7-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)
x(2 + x) (7−x) = 0
⇒ \(\left[{}\begin{matrix}x\left(2+x\right)=0\\7-x=0\end{matrix}\right.\)
❆ x(2 + x) = 0
x2 + xx = 0
x2 = 0 ; xx = 0
⇒ x = 0
❆ 7 - x = 0
x = 7 - 0
⇒ x = 7
➤ Vậy x ∈ {0; 7}