\(\left(x-a\right)\left(x^2+2ax+a^2\right)=0\\ \Leftrightarrow\left(x-a\right)\left(x+a\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}x-a=0\\x+a=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=a\\x=-a\end{matrix}\right.\)
Vậy x = a hoặc x = -a.