Bài 4: Phương trình tích
Các câu hỏi tương tự
giải phương trình
\(-6\left(-x^2-x+1\right)^4+x^2\left(-x^2-x+1\right)^2+5x^4=0\)
b) \(x^4+9=5x\left(x^2-3\right)\)
c) \(x^4+\left(x+1\right)\left(5x^2-6x-6\right)=0\)
d)\(\left(x^2+1\right)^2+\left(x+1\right)\left(3x^2+2x-2\right)=0\)
e) \(x^2\left(x-1\right)^2+x\left(x^2-1\right)=2\left(x+1\right)^2\)
Giái phương trình:
a, \(\left(x^2+x+1\right)\left(6-2x\right)=0\)
b,\(\left(x-1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)
c,\(\left(x^2-1\right)\left(x+2\right)\left(x-3\right)=\left(x-1\right)\left(x^2-4\right)\left(x+5\right)\)
Giải phương trình:
\(8\left(x+\dfrac{1}{x}\right)^2+4\left(x^2+\dfrac{1}{x^2}\right)^2-4\left(x^2+\dfrac{1}{x^2}\right)\left(x+\dfrac{1}{x}\right)^2=\left(x+4\right)^2\)
giúp mk chiều rùi
bài 1
a,\(\left(x-4\right)^2-25=0\)
b,\(\left(x-3\right)^2-\left(x+1\right)^2=0\)
c,\(\left(x^2-4\right)\left(21+3\right)=\left(x^2-4\right)\left(x-1\right)\)
d,\(\left(3x-7\right)^2-4\left(x+1\right)^2=0\)
\(\left(x+2\right)^2+\left(x-1\right)\left(x+3\right)=2\left(x-4\right)\left(x+4\right)-3\)
Giúp mk với!!!
Các bạn làm giúp mình bài này . Mình gấp lắm !
Giải phương trình :
\(\dfrac{1}{x\left(x-1\right)}+\dfrac{1}{\left(x-1\right)\left(x-2\right)}+\dfrac{1}{\left(x-2\right)\left(x-3\right)}+\dfrac{1}{\left(x-3\right)\left(x-4\right)}=\dfrac{1}{x-4}+2\)
Giải các phương trình sau :
a) left(x-1right)left(5x+3right)left(3x-8right)left(x-1right)
b) 3xleft(25x+15right)-35left(5x+3right)0
c) left(2-3xright)left(x+11right)left(3x-2right)left(2-5xright)
d) left(2x^2+1right)left(4x-3right)left(2x^2+1right)left(x-12right)
e) left(2x-1right)^2+left(2-xright)left(2x-1right)0
f) left(x+2right)left(3-4xright)x^2+4x+4
Đọc tiếp
Giải các phương trình sau :
a) \(\left(x-1\right)\left(5x+3\right)=\left(3x-8\right)\left(x-1\right)\)
b) \(3x\left(25x+15\right)-35\left(5x+3\right)=0\)
c) \(\left(2-3x\right)\left(x+11\right)=\left(3x-2\right)\left(2-5x\right)\)
d) \(\left(2x^2+1\right)\left(4x-3\right)=\left(2x^2+1\right)\left(x-12\right)\)
e) \(\left(2x-1\right)^2+\left(2-x\right)\left(2x-1\right)=0\)
f) \(\left(x+2\right)\left(3-4x\right)=x^2+4x+4\)
1,Giải PT sau
a,\(\frac{4}{5}x-3=\frac{1}{5}x\left(4x-15\right)\)
b,(x-3)-\(\frac{\left(x-3\right)\left(2x-5\right)}{6}=\frac{\left(x-3\right)\left(3-x\right)}{4}\)
c,\(\frac{\left(3x+1\right)\left(3x-2\right)}{3}+5\left(3x+1\right)=\) \(\frac{2\left(2x+1\right)\left(3x+1\right)}{3}+2x\left(3x+1\right)\)
tìm x biết
9left(x+2right)-3left(x+2right)0
xleft(x+5right)+left(x-3right)left(x+5right)03x^2+6x0
2left(2x-5right)-3x0
left(x-1right)^2+xleft(5-xright)0
left(2x-3right)left(2x+3right)-left(x+5right)^2-3left(x-1right)left(x+2right)0
left(2x-1right)^2-450
2x^2-6x0
giúp vs can gap
Đọc tiếp
tìm x biết
\(9\left(x+2\right)-3\left(x+2\right)=0\)
\(x\left(x+5\right)+\left(x-3\right)\left(x+5\right)=0\)\(3x^2+6x=0\)
\(2\left(2x-5\right)-3x=0\)
\(\left(x-1\right)^2+x\left(5-x\right)=0\)
\(\left(2x-3\right)\left(2x+3\right)-\left(x+5\right)^2-3\left(x-1\right)\left(x+2\right)\)=0
\(\left(2x-1\right)^2-45=0\)
\(2x^2-6x=0\)
giúp vs can gap