\(\sqrt{x+2}=\dfrac{5}{7}\)
\(\Leftrightarrow x+2=\dfrac{25}{49}\Rightarrow x=\dfrac{25}{49}-2=-\dfrac{73}{49}\)
Vậy........
\(\sqrt{x+2}=\dfrac{5}{7}\)
\(\Leftrightarrow\sqrt{x+2}^2=\dfrac{25}{49}\)
\(\Leftrightarrow\left|x+2\right|=\dfrac{25}{49}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=\dfrac{25}{49}\\x+2=-\dfrac{25}{49}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{73}{49}\\x=-\dfrac{123}{49}\end{matrix}\right.\)