\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0
\)
=> \(\left(x-7\right)^{x+1}=\left(x-7\right)^{x+11}\)
=> \(x+1=x+11\)
=> \(x+x=1+11\)
=> \(2x=12
\)
=> \(x=6\)
Vậy \(x=6\)
(x - 7)x+1 - (x - 7)x+11= 0
=>(x-7)x+1 = (x-7)x+11
=> x+1=x+11
=>1+11=x+x
=>12=2x
=>x=12:2
=>x=6