với x>0\(\left|x-7\right|=x-7\Rightarrow x-7+2x+5=6\Rightarrow3x=8\Rightarrow x=\dfrac{8}{3}\) |
với x<0\(\left|x-7\right|=7-x\Rightarrow7-x+2x+5=6\Rightarrow x=-6\Rightarrow x=6\) |
\(\left | x - 7 \right | + 2x + 5 =6\)
\(\left | x - 7 \right | =6 - 5 - 2x\)
\(\left | x - 7 \right | =1 - 2x\)
+ x - 7 = 1 - 2x
x + 2x = 1 + 7
3x = 8
=> x = \(\frac{8}{3}\)
+ x - 7 = - (1 - 2x)
x - 7 = - 1 + 2x
x - 2x = - 1 + 7
- x = 6
x = - 6
Vậy x = \(\frac{8}{3}\); x = - 6