\(\left(2x+\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\)
\(\left(2x+\dfrac{3}{5}\right)^2=\dfrac{9}{25}\)
\(\left(2x+\dfrac{3}{5}\right)^2=\left(\dfrac{3}{5}\right)^2\)
\(\Rightarrow\)\(2x+\dfrac{3}{5}=\dfrac{3}{5}\)
\(2x=0\)
\(\Rightarrow x=0\)
Vậy \(x=0\)