Ta có \(\frac{x}{3}\)+\(\frac{5}{6}\)=\(\frac{4}{3}\)
\(\frac{2x}{6}\)+\(\frac{5}{6}\)=\(\frac{8}{6}\)
\(\frac{2x+5}{6}\)=\(\frac{8}{6}\)
=>2x+5=8
2x=3
x=\(\frac{3}{2}\)
Bạn gì đó ơi \(\frac{3}{6}\)=\(\frac{1}{2}\) chứ sao lại \(\frac{1}{3}\)
\(\frac{x}{3}+\frac{5}{6}=\frac{4}{3}\)
\(\frac{x}{3}=\frac{4}{3}-\frac{5}{6}\)
\(\frac{x}{3}=\frac{8-5}{6}\)
\(\frac{x}{3}=\frac{3}{6}\)
\(\frac{x}{3}=\frac{1}{3}\)
\(x=1\)
Chúc bạn học tốt