a/ \(-4\frac{3}{5}\cdot2\frac{4}{23}=\left(-\frac{23}{5}\right)\cdot\frac{50}{23}=-10\)
\(-2\frac{3}{5}\cdot1\frac{6}{15}=\left(-\frac{13}{5}\right)\cdot\frac{7}{5}=-\frac{91}{25}=-\frac{3}{64}\)
Mà \(-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{5}\cdot1\frac{6}{15}\)
=> \(-10\le x\le-3.64\)
=> \(x=\left\{-10;-9;-8;-7;-6;-5;-4;-3\right\}\)