Question

Tìm x, biết:\(\left(2\frac{1}{5}+\frac{3}{5}x\right)=\frac{3}{4}\)

Answer 1

Ta có:

\(2\frac{1}{5}+\frac{3}{5}x=\frac{3}{4}\Rightarrow\frac{3}{5}x=\frac{3}{4}-2\frac{1}{5}=-\frac{29}{20}\Rightarrow x=-\frac{29}{20}:\frac{3}{5}=-\frac{29}{12}\)

Vậy \(x=-\frac{29}{12}\)

Answer 2

\(\left(2\frac{1}{5}+\frac{3}{5}x\right)=\frac{3}{4}\)

\(2\frac{1}{5}+\frac{3}{5}x=\frac{3}{4}\)

\(\frac{11}{5}+\frac{3}{5}x=\frac{3}{4}\)

\(\frac{3}{5}x=\frac{3}{4}-\frac{11}{5}=-\frac{29}{20}\)

\(x=\frac{-29}{20}:\frac{3}{5}=-\frac{29}{12}\)

Answer 3

\(\left(2\frac{1}{5}+\frac{3}{5}x\right)=\frac{3}{4}\)

\(\left(\frac{11}{5}+\frac{3}{5}x\right)=\frac{3}{4}\)

\(\frac{3}{5}x=\frac{3}{4}-\frac{11}{5}\)

\(\frac{3}{5}x=-\frac{29}{20}\)

\(x=-\frac{29}{20}:\frac{3}{5}=-\frac{29}{12}\)