Đoạn đó ( dưới ) :
\(\Rightarrow\left[\begin{array}{nghiempt}\frac{1}{4}x=2\\\frac{1}{4}x=-2\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=8\\x=-8\end{array}\right.\)
:)
Giải :
\(\frac{1}{4}\left|x\right|-2,5=-\frac{1}{2}\)
\(\Rightarrow\frac{1}{4}\left|x\right|=2\)
\(\Rightarrow\left[\begin{array}{nghiempt}\frac{1}{4}.x=2\\\frac{1}{4}.x=-2\end{cases}\Rightarrow\left[\begin{array}{nghiempt}x=8\\x=-8\end{array}\right.}\)
\(\frac{1}{4}\) \(\left|x\right|\) - \(2,5\) = \(-\frac{1}{2}\)
\(\frac{1}{4}\) \(\left|x\right|\) = \(-\frac{1}{2}\) + \(2,5\) = 2
\(\left|x\right|\) = \(2\) : \(\frac{1}{4}\)
\(\Rightarrow\)
\(x\) = 8\(x=-8\)\(\frac{1}{4}\left|x\right|-2,5=-\frac{1}{2}\)
\(\Rightarrow\frac{1}{4}\left|x\right|=-\frac{1}{2}+2,5=2\)
\(\Rightarrow\left|x\right|=-3:\frac{1}{4}=8\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=8\\x=-8\end{array}\right.\)
Vậy : \(\left[\begin{array}{nghiempt}x=8\\x=-8\end{array}\right.\)