`(1/7 x -2/7)(-1/5 x + 3/5)(1/3 x +4/3)=0`
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{7}x-\dfrac{2}{7}=0\\-\dfrac{1}{5}x+\dfrac{3}{5}=0\\\dfrac{1}{3}x+\dfrac{4}{3}=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{7}x=\dfrac{2}{7}\\-\dfrac{1}{5}x=-\dfrac{3}{5}\\\dfrac{1}{3}x=-\dfrac{4}{3}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\\x=-4\end{matrix}\right.\)