a) \(\frac{-x}{4}=\frac{-9}{x}\)
\(\Rightarrow x^2\left(-1\right)=-36\)
\(\Rightarrow x^2=6^2\)
\(\Rightarrow x=\pm6\)
Vậy \(x=\left[\begin{matrix}6\\-6\end{matrix}\right.\)
b) \(\frac{12}{x+1}=\frac{5}{30}\)
\(\Rightarrow\left(x+1\right)5=12.30\)
\(\Rightarrow5x+5=360\)
\(\Rightarrow5x=355\)
\(\Rightarrow x=355:5\)
\(\Rightarrow x=71\)
Vậy \(x=71.\)
c) \(\frac{x+42}{5}=\frac{5x+2}{20}\)
\(\Rightarrow\left(x+42\right)20=5\left(5x+2\right)\)
\(\Rightarrow20x+840=25x+10\)
\(\Rightarrow20x-25x=-840+10\)
\(\Rightarrow-5x=-830\)
\(\Rightarrow x=166\)
Vậy \(x=166.\)
a, \(\frac{-x}{4}=\frac{-9}{x}\Rightarrow-x.x=-9.4\)
\(\Rightarrow-x.x=-36=-6.6\Rightarrow x=6\)
Vậy x = 6
b, \(\frac{12}{x+1}=\frac{5}{30}=\frac{1}{6}\Rightarrow x+1=12.6\)
\(\Rightarrow x+1=72\Rightarrow x=72-1=71\)
Vậy x = 71
c, \(\frac{x+42}{5}=\frac{5x+2}{20}\Rightarrow20\left(x+42\right)=5\left(5x+2\right)\)
\(\Rightarrow20x+840=25x+10\Rightarrow20x-25x=-840+10\)
\(\Rightarrow\left(20-25\right)x=-830\Rightarrow-5x=-830\)
\(\Rightarrow x=-830\div\left(-5\right)\Rightarrow x=166\)
Vậy x = 166
