Question

Tìm x biết :

a, ( x + 1 )² = ( x + 1 )⁴

b, ( x - 2 )⁵ = ( x - 2 )³

c, ( 2x - 1 )² = ( 2x - 1 )⁴

Answer 1

A) X=0

Answer 2

a: \(\Leftrightarrow\left(x+1\right)^2\left[\left(x+1\right)^2-1\right]=0\)

=>(x+1)^2(x+2)*x=0

hay \(x\in\left\{0;-1;-2\right\}\)

b: \(\Leftrightarrow\left(x-2\right)^3\left[\left(x-2\right)^2-1\right]=0\)

=>\(\left(x-2\right)^3\left(x-3\right)\left(x-1\right)=0\)

hay \(x\in\left\{2;3;1\right\}\)

c: \(\Leftrightarrow\left(2x-1\right)^2\left[\left(2x-1\right)^2-1\right]=0\)

=>\(\left(2x-1\right)^2\cdot2x\cdot\left(2x-2\right)=0\)

hay \(x\in\left\{0;\dfrac{1}{2};1\right\}\)