a, đầu bài sai hay sao đó bn
b,\(\dfrac{2}{3}\).3x+1 - 7.3x = -405
3x(\(\dfrac{2}{3}\).3 - 7) = -405
3x . (-5) = -405
3x = 81 mà 81 = 34 suy ra x = 4
a, đầu bài sai hay sao đó bn
b,\(\dfrac{2}{3}\).3x+1 - 7.3x = -405
3x(\(\dfrac{2}{3}\).3 - 7) = -405
3x . (-5) = -405
3x = 81 mà 81 = 34 suy ra x = 4
Tìm x biết:
a) \(x:\left(-\dfrac{1}{2}\right)^3=-\dfrac{1}{2}\); b) \(\left(\dfrac{3}{4}\right)^5.x=\left(\dfrac{3}{4}\right)^7\)
a ) (-\(\)\(\dfrac{4}{3}\)x + \(\dfrac{1}{2}\))2 = \(\dfrac{1}{4}\)
b) 3 x + 3 x+2= 20
c) ( \(\dfrac{1}{2}\)) x+ (\(\dfrac{1}{2}\))x+2= \(\dfrac{5}{4}\)
Giúp mk với !!! Ngày mai mk làm kiểm tra rồi !!! PLEASE
1. Tìm các số nguyên x,y biết :
a) \(^{3^{4-x}}\)-x = 2
b)3^-1.4^x + 3.4^x = \(\dfrac{5}{3}\).\(^{2^7}\)
bài 1 tìm x biết
a/ \(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{-1}{5}x+\dfrac{3}{4}\)
b/ (x-3)5 \(=32^2\)
c/ \(\left(2x+1\right)^3=27^2\)
d/ \(5^{x+3}=0,04\)
e/ \(x^2+2x-24=0\)
f/ \(x^2-10x+21=0\)
a) \(x:\left(-\dfrac{1}{2}\right)^3=-\dfrac{1}{2}\)
b)\(\left(\dfrac{3}{4}\right)^2.x=\left(\dfrac{3}{4}\right)^5\)
1,Tìm x,biết
a,\(\left(-1\dfrac{3}{5}+x\right)\div\dfrac{12}{13}=2\dfrac{1}{6}\)
b,\(\dfrac{-4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}\div\left(-1\dfrac{2}{3}\right)\)
Tìm x biết:
1) \(\dfrac{x+1}{2}+\dfrac{x+1}{3}+\dfrac{x+1}{4}=\dfrac{x+1}{5}+\dfrac{x+1}{6}\)
2) \(\dfrac{x+1}{2009}+\dfrac{x+2}{2008}+\dfrac{x+3}{2007}=\dfrac{x+10}{2000}+\dfrac{x+11}{1999}+\dfrac{x+12}{1998}\)
Bài 1: Tìm n \(\in\) Z biết:
\(e)3^{-1}.3^n+6.3^{n-1}=7.3^6\)
\(g)3^4< \dfrac{1}{9}.27^n< 3^{10}\)
\(h)25< 5^n:5< 625\)
Bài 2: Tìm x biết:
\(\dfrac{2.\left(\dfrac{-1}{2}\right).\left(\dfrac{2}{3}\right)^2-3.\left(\dfrac{-1}{2}\right)^2.\dfrac{2}{3}+1}{3.\left(\dfrac{-1}{2}\right)-\dfrac{2}{3}}\)
Help me !!!!!!!!!!!!! giúp mk vs các bn giỏi toán
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)