TH1: 2x - 6 ≥ 0 <=> x ≥ 3
=> |2x - 6| + 5x = 2x - 6 + 5x = 9
<=> 7x - 6 = 9 <=> 7x = 15 <=> x = 15/7 (loại)
TH2: 2x - 6 < 0 <=> x < 3
=> |2x - 6| + 5x = -2x + 6 +5x = 9
<=> 3x + 6 = 9 <=> 3x = 3 <=> x = 1 (tm)
Vậy x = 1
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\(\left|2x-6\right|+5x=9\)
* TH1: \(\left|2x-6\right|+5x=9\Leftrightarrow2x-6+5x=9\)
\(\Leftrightarrow7x-6=9\Leftrightarrow x=\dfrac{15}{7}\)
* TH2: \(\left|2x-6\right|+5x=9\)
\(\Leftrightarrow-2x+6+5x=9\Leftrightarrow3x+6=9\Leftrightarrow x=1\)
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